## Introduction

Big-O notation (pronounced ‘Big Oh’) is used in computer science as a means to describe the worst-case performance of an algorithm. It’s one of the things you really should learn if you’re interested at all in designing efficient algorithms.

The formal definition is as follows:

f(n) = O(g(n)) means cg(n) is an upper bound on f(n). Thus there exists some constant c such that f(n) is always \leq cg(n), for large enough n (i.e. n \geq n_0 for some constant n_0).

This definition is a very formal way of saying that Big-O notation is the upper-bound/worst-case of a function.

## Worst-case

Big-O notation has a counterpart Ω-notation (Big Omega notation), which describes the best-case instead of the worst-case. While it may seem unintuitive, this is actually much less useful when analysing performance issues. In general we care much more about the worst-case performance as we want everything to run as smooth as possible, not randomly fast and randomly slow. Consider the following function:

```
public Boolean doesTextContainChar(String text, char character) {
for (int i = 0; i < text.length(); i++) {
if (text.charAt(i) == character) {
return true;
}
}
return false;
}
```

If we run this function when `text`

is very small or when `character`

is near the beginning of `text`

then it will run very quickly. But what about when `text`

is extremely long and `character`

doesn’t exist? This is the worst-case of the algorithm.

## Simplicity

Big-O notation ignores the details of an algorithm and focuses only on the largest power in the term. A precise analysis of an algorithm could look something like this:

The beauty of Big-O notation is that we can ignore most of this and just focus on the largest term. We can even ignore the constant, consider the same algorithm written in a low-level language runs 3 times faster than when written in a high-level language, it’s a detail that isn’t really important when looking at the algorithm itself. So the function above in Big-O notation is

## O(1)

An O(1) function always runs in the same time regardless of the input size.

```
public Boolean isCharCaps(char character) {
int asciiCode = (int)character;
return asciiCode >= 65 && asciiCode <= 90;
}
```

## O(\log n)

An O(\log n) function grows at a rate of the logarithm (base 2) of the input size. A lot of sorted array search algorithms like the binary search algorithm are O(\log n). This is only really possible when you can ignore input elements entirely.

```
public Boolean binarySearch(int[] sortedArray, int value, int min, int max) {
if (max < min)
return false;
else {
int mid = (min + max) / 2;
if (sortedArray[mid] > value)
return BinarySearch(sortedArray, value, min, mid-1);
else if (sortedArray[mid] < value)
return BinarySearch(sortedArray, value, mid+1, max);
else
return true;
}
}
```

## O(n)

An O(n) function grows at the same rate as the input size.

```
public Boolean doesTextContainChar(String text, char character) {
for (int i = 0; i < text.length(); i++) {
if (text.charAt(i) == character) {
return true;
}
}
return false;
}
```

## O(n^2)

An O(n^2) function grows at a rate of input size to the power of 2.

```
public static int[] insertionSort(int[] array) {
for (int i = 1; i < array.length; i++) {
int item = array[i];
int indexHole = i;
while (indexHole > 0 && array[indexHole - 1] > item) {
array[indexHole] = array[--indexHole];
}
array[indexHole] = item;
}
return array;
}
```

More information on insertion sort can be found here.

## O(2^n)

An O(2^n) function’s time doubles whenever the input grows. If your function is O(2^n) it’s going to really struggle when the size of your input data increases even a little. Writing one would make me feel a little icky.